67 lines
1.6 KiB
C++
67 lines
1.6 KiB
C++
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#include <iostream>
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#include <thread>
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#include <queue>
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#include <mutex>
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#include <semaphore>
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using namespace std;
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#define LOOP_TIMES 1
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void test1() {
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int res = 0;
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binary_semaphore bs(0);
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thread t1([&]() {
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this_thread::sleep_for(chrono::milliseconds(1000));
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res = 12;
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bs.release();
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});
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t1.detach();
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bs.acquire();
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std::cout << "test1:: res "<< res << endl;
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}
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void test2() {
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int res = 0;
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counting_semaphore<> cs(0);
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queue<int> mq;
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mutex mtx;
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auto p = [&]() {
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for (int i = 0; i < LOOP_TIMES * 2; i++) {
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{ //保证res 与 mq 的修改线程安全
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std::this_thread::sleep_for(std::chrono::milliseconds(1000));
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lock_guard<mutex> lock(mtx);
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mq.push(i / 2);
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res = res + 1;
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}
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cs.release();
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}
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std::cout << "product end " << res << "\n";
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};
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auto c = [&](int id) {
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for (int i = 0; i < LOOP_TIMES; i++) {
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cs.acquire();//这里不存在虚假唤醒，一定能抢到资源，只是资源顺序不确定
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{
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lock_guard<mutex> lock(mtx);
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mq.pop();
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res = res - 1;
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}
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}
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std::cout << "consume end " << id << " -> " << res << "\n";
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};
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thread t1(p);
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thread t2(c, 1);
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thread t3(c, 2);
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t1.join();
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t2.join();
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t3.join();
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std::cout << "test1:: res " << res << " mq " << mq.size() << endl;
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}
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int main() {
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test1();
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test2();
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//信号量可以实现一批资源的分配
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//信号量可由条件变量与锁实现
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//信号量封装后可以实现chanel效果
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std::cout << "binary_semaphore size:: " << sizeof(binary_semaphore) <<
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" counting_semaphore<3> size:: " << sizeof(counting_semaphore<3>)<<
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" counting_semaphore<10> size:: " << sizeof(counting_semaphore<10>) << endl;
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return 1;
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}
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